3.50 \(\int x^{13} (a^2+2 a b x^3+b^2 x^6)^{5/2} \, dx\)

Optimal. Leaf size=255 \[ \frac{b^5 x^{29} \sqrt{a^2+2 a b x^3+b^2 x^6}}{29 \left (a+b x^3\right )}+\frac{5 a b^4 x^{26} \sqrt{a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}+\frac{10 a^2 b^3 x^{23} \sqrt{a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac{a^3 b^2 x^{20} \sqrt{a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac{5 a^4 b x^{17} \sqrt{a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac{a^5 x^{14} \sqrt{a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )} \]

[Out]

(a^5*x^14*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(14*(a + b*x^3)) + (5*a^4*b*x^17*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(
17*(a + b*x^3)) + (a^3*b^2*x^20*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(2*(a + b*x^3)) + (10*a^2*b^3*x^23*Sqrt[a^2 +
2*a*b*x^3 + b^2*x^6])/(23*(a + b*x^3)) + (5*a*b^4*x^26*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(26*(a + b*x^3)) + (b
^5*x^29*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(29*(a + b*x^3))

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Rubi [A]  time = 0.0636303, antiderivative size = 255, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077, Rules used = {1355, 270} \[ \frac{b^5 x^{29} \sqrt{a^2+2 a b x^3+b^2 x^6}}{29 \left (a+b x^3\right )}+\frac{5 a b^4 x^{26} \sqrt{a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}+\frac{10 a^2 b^3 x^{23} \sqrt{a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac{a^3 b^2 x^{20} \sqrt{a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac{5 a^4 b x^{17} \sqrt{a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac{a^5 x^{14} \sqrt{a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )} \]

Antiderivative was successfully verified.

[In]

Int[x^13*(a^2 + 2*a*b*x^3 + b^2*x^6)^(5/2),x]

[Out]

(a^5*x^14*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(14*(a + b*x^3)) + (5*a^4*b*x^17*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(
17*(a + b*x^3)) + (a^3*b^2*x^20*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(2*(a + b*x^3)) + (10*a^2*b^3*x^23*Sqrt[a^2 +
2*a*b*x^3 + b^2*x^6])/(23*(a + b*x^3)) + (5*a*b^4*x^26*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(26*(a + b*x^3)) + (b
^5*x^29*Sqrt[a^2 + 2*a*b*x^3 + b^2*x^6])/(29*(a + b*x^3))

Rule 1355

Int[((d_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_.) + (c_.)*(x_)^(n2_.))^(p_), x_Symbol] :> Dist[(a + b*x^n + c*x^
(2*n))^FracPart[p]/(c^IntPart[p]*(b/2 + c*x^n)^(2*FracPart[p])), Int[(d*x)^m*(b/2 + c*x^n)^(2*p), x], x] /; Fr
eeQ[{a, b, c, d, m, n, p}, x] && EqQ[n2, 2*n] && EqQ[b^2 - 4*a*c, 0] && IntegerQ[p - 1/2]

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rubi steps

\begin{align*} \int x^{13} \left (a^2+2 a b x^3+b^2 x^6\right )^{5/2} \, dx &=\frac{\sqrt{a^2+2 a b x^3+b^2 x^6} \int x^{13} \left (a b+b^2 x^3\right )^5 \, dx}{b^4 \left (a b+b^2 x^3\right )}\\ &=\frac{\sqrt{a^2+2 a b x^3+b^2 x^6} \int \left (a^5 b^5 x^{13}+5 a^4 b^6 x^{16}+10 a^3 b^7 x^{19}+10 a^2 b^8 x^{22}+5 a b^9 x^{25}+b^{10} x^{28}\right ) \, dx}{b^4 \left (a b+b^2 x^3\right )}\\ &=\frac{a^5 x^{14} \sqrt{a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac{5 a^4 b x^{17} \sqrt{a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac{a^3 b^2 x^{20} \sqrt{a^2+2 a b x^3+b^2 x^6}}{2 \left (a+b x^3\right )}+\frac{10 a^2 b^3 x^{23} \sqrt{a^2+2 a b x^3+b^2 x^6}}{23 \left (a+b x^3\right )}+\frac{5 a b^4 x^{26} \sqrt{a^2+2 a b x^3+b^2 x^6}}{26 \left (a+b x^3\right )}+\frac{b^5 x^{29} \sqrt{a^2+2 a b x^3+b^2 x^6}}{29 \left (a+b x^3\right )}\\ \end{align*}

Mathematica [A]  time = 0.0255999, size = 83, normalized size = 0.33 \[ \frac{x^{14} \sqrt{\left (a+b x^3\right )^2} \left (897260 a^2 b^3 x^9+1031849 a^3 b^2 x^6+606970 a^4 b x^3+147407 a^5+396865 a b^4 x^{12}+71162 b^5 x^{15}\right )}{2063698 \left (a+b x^3\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[x^13*(a^2 + 2*a*b*x^3 + b^2*x^6)^(5/2),x]

[Out]

(x^14*Sqrt[(a + b*x^3)^2]*(147407*a^5 + 606970*a^4*b*x^3 + 1031849*a^3*b^2*x^6 + 897260*a^2*b^3*x^9 + 396865*a
*b^4*x^12 + 71162*b^5*x^15))/(2063698*(a + b*x^3))

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Maple [A]  time = 0.009, size = 80, normalized size = 0.3 \begin{align*}{\frac{{x}^{14} \left ( 71162\,{b}^{5}{x}^{15}+396865\,a{b}^{4}{x}^{12}+897260\,{a}^{2}{b}^{3}{x}^{9}+1031849\,{a}^{3}{b}^{2}{x}^{6}+606970\,{a}^{4}b{x}^{3}+147407\,{a}^{5} \right ) }{2063698\, \left ( b{x}^{3}+a \right ) ^{5}} \left ( \left ( b{x}^{3}+a \right ) ^{2} \right ) ^{{\frac{5}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^13*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x)

[Out]

1/2063698*x^14*(71162*b^5*x^15+396865*a*b^4*x^12+897260*a^2*b^3*x^9+1031849*a^3*b^2*x^6+606970*a^4*b*x^3+14740
7*a^5)*((b*x^3+a)^2)^(5/2)/(b*x^3+a)^5

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Maxima [A]  time = 1.06016, size = 77, normalized size = 0.3 \begin{align*} \frac{1}{29} \, b^{5} x^{29} + \frac{5}{26} \, a b^{4} x^{26} + \frac{10}{23} \, a^{2} b^{3} x^{23} + \frac{1}{2} \, a^{3} b^{2} x^{20} + \frac{5}{17} \, a^{4} b x^{17} + \frac{1}{14} \, a^{5} x^{14} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^13*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="maxima")

[Out]

1/29*b^5*x^29 + 5/26*a*b^4*x^26 + 10/23*a^2*b^3*x^23 + 1/2*a^3*b^2*x^20 + 5/17*a^4*b*x^17 + 1/14*a^5*x^14

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Fricas [A]  time = 1.65686, size = 144, normalized size = 0.56 \begin{align*} \frac{1}{29} \, b^{5} x^{29} + \frac{5}{26} \, a b^{4} x^{26} + \frac{10}{23} \, a^{2} b^{3} x^{23} + \frac{1}{2} \, a^{3} b^{2} x^{20} + \frac{5}{17} \, a^{4} b x^{17} + \frac{1}{14} \, a^{5} x^{14} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^13*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="fricas")

[Out]

1/29*b^5*x^29 + 5/26*a*b^4*x^26 + 10/23*a^2*b^3*x^23 + 1/2*a^3*b^2*x^20 + 5/17*a^4*b*x^17 + 1/14*a^5*x^14

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{13} \left (\left (a + b x^{3}\right )^{2}\right )^{\frac{5}{2}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**13*(b**2*x**6+2*a*b*x**3+a**2)**(5/2),x)

[Out]

Integral(x**13*((a + b*x**3)**2)**(5/2), x)

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Giac [A]  time = 1.10066, size = 142, normalized size = 0.56 \begin{align*} \frac{1}{29} \, b^{5} x^{29} \mathrm{sgn}\left (b x^{3} + a\right ) + \frac{5}{26} \, a b^{4} x^{26} \mathrm{sgn}\left (b x^{3} + a\right ) + \frac{10}{23} \, a^{2} b^{3} x^{23} \mathrm{sgn}\left (b x^{3} + a\right ) + \frac{1}{2} \, a^{3} b^{2} x^{20} \mathrm{sgn}\left (b x^{3} + a\right ) + \frac{5}{17} \, a^{4} b x^{17} \mathrm{sgn}\left (b x^{3} + a\right ) + \frac{1}{14} \, a^{5} x^{14} \mathrm{sgn}\left (b x^{3} + a\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^13*(b^2*x^6+2*a*b*x^3+a^2)^(5/2),x, algorithm="giac")

[Out]

1/29*b^5*x^29*sgn(b*x^3 + a) + 5/26*a*b^4*x^26*sgn(b*x^3 + a) + 10/23*a^2*b^3*x^23*sgn(b*x^3 + a) + 1/2*a^3*b^
2*x^20*sgn(b*x^3 + a) + 5/17*a^4*b*x^17*sgn(b*x^3 + a) + 1/14*a^5*x^14*sgn(b*x^3 + a)